Linear Depreciation
When linear Depreciation is selected, the acquisition value is evenly distributed over the Depreciation Period. When the acquisition value is for example EUR 120'000 and the Depreciation Period is 10 years respective 120 months, the expense is evenly distributed over the 120 months.
| ∑ | 01.2016 | 02.2016 | 03.2016 | 04.2016 | 05.2016 | 06.2016 | 07.2016 | 08.2016 | 09.2016 | 10.2016 | 11.2016 | 12.2016 | ... | 12.2025 |
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Profit & Loss statement | -120'000 | -1'000 | -1'000 | -1'000 | -1'000 | -1'000 | -1'000 | -1'000 | -1'000 | -1'000 | -1'000 | -1'000 | -1'000 | ... | -1'000 |
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Degressiv Depreciation
When degressiv Depreciation is selected, the Depreciation amount is the product of the book value from the previous period and the Depreciation Rate. When the acquisition value is for example EUR 120'000 and the Depreciation Rate is 40%, the Depreciation amount in the first year is EUR 48'000. On monthly basis the Depreciation Rate is 1-(1-0.4)^(1/12) = 4.17%. Thus there is a Depreciation amount of EUR 5'001 in the first month. The book value after Depreciation equals EUR 120'000 - EUR 5'001= EUR 114'999. The second month Depreciation amount is EUR 4'793.
With degressiv Deprecation method, there is never a book value of 0. Because of that, a Residual Write-Off is made on a defined date. In the following example the Residual Write-Off is after 10 years in December 2025.
| ∑ | 01.2016 | 02.2016 | 03.2016 | 04.2016 | 05.2016 | 06.2016 | 07.2016 | 08.2016 | 09.2016 | 10.2016 | 11.2016 | 12.2016 | ... | 12.2025 |
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Profit & Loss statement | -120'000 | -5'001 | -4'793 | -4'593 | -4'401 | -4'218 | -4'042 | -3'874 | -3'712 | -3'558 | -3'409 | -3'267 | -3'131 | ... | -757 |
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When immediate Depreciation is selected, the whole acquisition value is written down on a defined date. When the acquisition value is for example EUR 120'000 and the Due Date is 04.2016 the whole acquisition value is written down on this date.
| ∑ | 01.2016 | 02.2016 | 03.2016 | 04.2016 | 05.2016 | 06.2016 | 07.2016 | 08.2016 | 09.2016 | 10.2016 | 11.2016 | 12.2016 | ... | 12.2025 |
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Profit & Loss statement | -120'000 | 0 | 0 | 0 | -120'000 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | ... | 0 |
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Appreciation
When Appreciation is selected as method, the Appreciation amount is the product of the book value from the previous period and the Appreciation Rate. When the acquisition value is for example EUR 120'000 and the Appreciation Rate is 5%, the Appreciation amount in the first year is EUR 6'000. On monthly basis the Appreciation Rate is 1-(1-0.05)^(1/12) = 0.42%. Thus there is an Appreciation amount of EUR 512 in the first month. The book value after Appreciation equals EUR 120'000 + EUR 512= EUR 120'512. The second month Appreciation amount is EUR 514.
| ∑ | 01.2016 | 02.2016 | 03.2016 | 04.2016 | 05.2016 | 06.2016 | 07.2016 | 08.2016 | 09.2016 | 10.2016 | 11.2016 | 12.2016 |
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Profit & Loss statement | -120'000 | 512 | 514 | 516 | 518 | 521 | 523 | 525 | 527 | 530 | 532 | 534 | 536 |
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